Question

The equilibrium constant is given for two of the reactions below. Determine the value of the...

The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g) + B(g) ⇌ A2B(g) Kc = ? A2B(g) + B(g) ⇌ A2B2(g) Kc = 16.4 2A(g) + 2B(g) ⇌ A2B2(g) Kc = 28.2

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Answer #1

A2B(g) + B(g) ⇌ A2B2(g) Kc = 16.4 ------- Eq (1)

2A(g) + 2B(g) ⇌ A2B2(g) Kc = 28.2 ------- Eq (2)

Take reverse of Eq (1)

A2B2(g) ⇌ A2B(g) + B(g) Kc = 1/16.4 --- Eq(3)

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2A(g) + 2B(g) ⇌ A2B2(g) Kc = 28.2 ------- Eq (2)

A2B2(g) ⇌ A2B(g) + B(g) Kc = 1/16.4 --- Eq(3)

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add eqs (2) and (3) and cancel similar terms

Hence, the resultant equation is

2A(g) + B(g) ⇌ A2B(g)

Kc =  28.2 x 1/16.4 = 1.72

Therefore,

2A(g) + B(g) ⇌ A2B(g) Kc = 1.72

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