Question

An aqueous solution of **copper(II) iodide** has a
concentration of **0.448** molal.

The percent by mass of **copper(II) iodide** in the
solution is _______%

Answer #1

**let mass of solvent be 1 Kg**

**m(solvent)= 1 Kg**

**number of mol,**

**n = Molality * mass of solvent in Kg**

**= (0.448 mol/Kg)*(1 Kg)**

**= 0.448 mol**

**Molar mass of CuI2,**

**MM = 1*MM(Cu) + 2*MM(I)**

**= 1*63.55 + 2*126.9**

**= 317.35 g/mol**

**mass of CuI2,**

**m = number of mol * molar mass**

**= 0.448 mol * 317.35 g/mol**

**= 142.2 g**

**SO,**

**mass of solution = mass of solvent + mass of
CuI2**

**= 1000 g + 142.2 g**

**= 1142.2 g**

**mass % of CuI2 = mass of CuI2 * 100 / mass of
solution**

**= 142.2 * 100 / 1142.2**

**= 12.4 %**

**Answer: 12.4 %**

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