A sample containing 3.4 mol of a monatomic ideal gas was heated from 15.9
+Since - according to Charles-Gaulussac's law
T2 / T1 = V2 / V1
Where, T1 = 15.9+273 = 288.9 K
T2 = 87+273 = 360 K
and we can use the following formula to calculate the entropy change,
Since - DS = DH / T = [nRT ln (V2/V1) ] / T = nR ln (V2/V1)
Thus - DS = (3.4)(8.314) ln (360/288.9)
= = - 6.219 J/K
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