Fundamentals Of Analytical Chemistry 9th Edition - Skoog
Balance the net ionic equation of the following redox reaction using half-reaction method. Show the steps.
Cr(OH)3 + ClO3- --------> CrO42- + Cl- (basic medium)
Cr(OH)3+H2O---->CrO4-2+5H++3e- (1)
ClO3-+6H++6e----------->Cl-+3H2O (2)
Multiplying equation (1) by 2
gives 2Cr(OH)3+2H2O--------->2CrO4-2+10H++6e- (3)
Addition of Equation (2) and Equation (3) gives
2Cr(OH)3+2H2O+ClO3- +6H++6e-------->2CrO4-2+10H+ +6e- +Cl-+3H2O
2Cr(OH)3 (aq)+ClO3- (aq)--------> 2CrO4-2 (aq)+4H+(aq)+Cl-(aq)+H2O(l)
Since there are 4H+ to make them neutral, add 4OH-
2Cr(OH)3(aq)+ClO3- (aq) +4OH - (aq) ------------> 2CrO4-2 (aq)+4H+ +4OH- +Cl-(aq)+H2O
2Cr(OH)3 (aq)+ClO3-(aq)+4OH- (aq) ---------->2CrO4-2(aq)+5H2O(l) +Cl-(aq)
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