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Calculate the equilibrium constant, K, for the following reaction at 25 °C. Fe^3+(aq)+B(s) + 6H2O(l) -->...

Calculate the equilibrium constant, K, for the following reaction at 25 °C. Fe^3+(aq)+B(s) + 6H2O(l) --> Fe(s) + H3BO3(s) + 3H3O+(aq) The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E°) are as follows:

Fe3+(aq) + 3e- --> Fe (s)... E=-0.04V
H3BO3(s) + 3H3O+(aq) + 3e- ---> B(s)+6H20 (l).....E=-0.8698

K=?

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