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A mixture of 0.00100mol of gas A and 0.00200mol of gas B was allowed to reach...

A mixture of 0.00100mol of gas A and 0.00200mol of gas B was allowed to reach equilibrium in a 2.00L vessel. A(g) + 2B(g) ↔ AB2(g). at equilibrium, the contained 0.00080mol of AB2. How many mols of B were in the vessel equilibrium? What is the value of K?

Answers: .00040 mol B

K=1.0x10^8 please explain these answers

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