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A 47.5 block of an unknown metal is heated in a hot water bath to 100...

A 47.5 block of an unknown metal is heated in a hot water bath to 100 degrees Celsius. When the block is placed in an insulated vessel containing 130.0 g of water at 25.0 degrees Celsius, the final temperature is 28.0 degrees Celsius. Determine the specific heat of the unknown metal. The Cs for water is 4.18 J/g degrees Celsius.
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Answer #1

Heat lose of metal       = Heat gain of water

mct                       =   mct

47.5*C*(100-28)         =   130*4.18*(28-25)

3420*C                     = 1630.2

C                             = 1630.2/3420 = 0.476j/g

specific heat of metal    = 0.476j/g

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