Consider the titration of a 27.0-mLmL sample of 0.175 MM CH3NH2CH3NH2 with 0.150 MM HBrHBr. (The value of KbKb for CH3NH2CH3NH2 is 4.4×10−44.4×10−4.)
Determine the volume of added acid required to reach the equivalence point.
Determine the pHpH after adding 4.0 mLmL of acid beyond the equivalence point.
Get Answers For Free
Most questions answered within 1 hours.