Question

Precipitation Learning Goal: To understand the relationship between precipitation and the solubility product and to be...

Precipitation

Learning Goal:

To understand the relationship between precipitation and the solubility product and to be able to predict whether a substance will precipitate or not.

Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq) , precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to decrease the concentrations of A+ and B− . This critical level, Ksp , is a constant at a certain temperature. In this case, Q=[A+][B−] . where Q is the ion product.

When Q>Ksp , precipitation occurs until Q is equal to Ksp .

When QKsp , a precipitate does not form.

Part A - Calculate the value of Q What is the value of Q when the solution contains 2.00×10−3 M C a 2+ and 3.00× 10 −2 M S O 4 2− ? Express your answer numerically.

Part C What concentration of the barium ion, B a 2+ , must be exceeded to precipitate Ba F 2 from a solution that is 1.00× 10 −2 M in the fluoride ion, F − ? K sp for barium fluoride is 2.45×10−5 . Express your answer with the appropriate units.

Homework Answers

Answer #1

CaSO4   ----------------> Ca+2 + SO42-

Q = [Ca+2][SO42-]

   = (2.00×10^−3)(3.00× 10^ −2)

Q = 6.00 x 10^-5

Ksp = 4.93 x 10^-5

here Q > Ksp .so precipitate forms

Part C)

BaF2   ---------------> Ba+2 + 2F-

                                   Ba+2    1 x 10^-2

Ksp = [Ba+2][F-]^2

2.45×10^−5 = [Ba+2](1 x 10^-2)^2

[Ba+2] = 0.245 M

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able...
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able to predict whether a substance will precipitate or not. Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to...
An aqueous solution of sodium fluoride is slowly added to a water sample that contains barium...
An aqueous solution of sodium fluoride is slowly added to a water sample that contains barium ion (4.15×10-2 M ) and calcium ion (3.55×10-2 M ). The Ksp of barium fluoride is 1.00x10–6. The Ksp of calcium fluoride is 3.90x10–11. What is the remaining concentration of the first ion to precipitate when the second ion begins to precipitate?
± Common-Ion Effect on Solubility for Lead Thiocyanate Lead thiocyanate, Pb(SCN)2, has a Ksp value of...
± Common-Ion Effect on Solubility for Lead Thiocyanate Lead thiocyanate, Pb(SCN)2, has a Ksp value of 2.00×10−5. Part A Calculate the molar solubility of lead thiocyanate in pure water. The molar solubility is the maximum amount of lead thiocyanate the solution can hold. Express your answer with the appropriate units. SubmitHintsMy AnswersGive UpReview Part Common-Ion Effect Consider the dissolution of AB(s) : AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−] will shift this equilibrium...
The solubility-product constants, Ksp, at 25 ∘C for two compounds [iron(II) carbonate, FeCO3, and cadmium(II) carbonate,...
The solubility-product constants, Ksp, at 25 ∘C for two compounds [iron(II) carbonate, FeCO3, and cadmium(II) carbonate, CdCO3] are given by the table Part A A solution of Na2CO3 is added dropwise to a solution that contains 1.04×10−2M Fe2+ and 1.50×10−2M Cd2+. What concentration of CO32− is need to initiate precipitation? Neglect any volume changes during the addition. Express the molar concentration numerically. Part B In the solution from Part A, what will the concentration of CO32− be when Fe2+ begins...
Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either...
Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−] will shift this equilibrium to the left, reducing the solubility of AB. In other words, AB is more soluble in pure water than in a solution that already contains A+ or B− ions. This is an example of the common-ion effect. The generic metal hydroxide M(OH)2 has Ksp = 5.85×10−18. Part A What is the solubility of M(OH)2 in pure water?...
Barium and Calcium ions in aqueous solutions can be separated by the differences in their solubilizes...
Barium and Calcium ions in aqueous solutions can be separated by the differences in their solubilizes as fluoride salts( Baf2, Ksp=1.8E-7 and CaF2, ksp=5.3E-11. a) which salt precipitates first when slowly adding fluoride ion to a solution that is .1 M In both Ba and Ca? Explain. b) wat concentration of fluoride ion will precipitate the maximum amount of the first salt from the solution described in "part a" while not precipitating the second? Explain.
± Solubility of Zinc Hydroxide in Basic Solution The solubility-product constant for Zn(OH)2 is Ksp=3.00×10−16. The...
± Solubility of Zinc Hydroxide in Basic Solution The solubility-product constant for Zn(OH)2 is Ksp=3.00×10−16. The formation constant for the hydroxo complex, Zn(OH)42−, is Kf=4.60×1017. A solubility-product constant, Ksp, corresponds to a reaction with the following general format: salt(s)⇌cation(aq)+anion(aq) A formation constant, Kf, corresponds to a reaction with the following general format: metal ion(aq)+Lewis base(aq)⇌complex ion(aq) Part A When Zn(OH)2(s) was added to 1.00 L of a basic solution, 1.01×10−2 mol of the solid dissolved. What is the concentration of...
Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either...
Consider the dissolution of AB(s): AB(s)⇌A+(aq)+B−(aq) Le Châtelier's principle tells us that an increase in either [A+] or [B−] will shift this equilibrium to the left, reducing the solubility of AB. In other words, AB is more soluble in pure water than in a solution that already contains A+ or B− ions. This is an example of the common-ion effect. The generic metal hydroxide M(OH)2 has Ksp = 1.05×10−18. (NOTE: In this particular problem, because of the magnitude of the...
The solubility-product constant for Zn(OH)2 is Ksp=3.00×10−16. The formation constant for the hydroxo complex, Zn(OH)42−, is...
The solubility-product constant for Zn(OH)2 is Ksp=3.00×10−16. The formation constant for the hydroxo complex, Zn(OH)42−, is Kf=4.60×1017. A solubility-product constant, Ksp, corresponds to a reaction with the following general format: salt(s)⇌cation(aq)+anion(aq) A formation constant, Kf, corresponds to a reaction with the following general format: metal ion(aq)+Lewis base(aq)⇌complex ion(aq) Part A When Zn(OH)2(s) was added to 1.00 L of a basic solution, 1.20×10−2 mol of the solid dissolved. What is the concentration of OH− in the final solution? Express your answer...
What range of pH would permit the selective precipitation of Cu2+ as Cu(OH)2 from a solution...
What range of pH would permit the selective precipitation of Cu2+ as Cu(OH)2 from a solution that contains 0.088 M Cu2+ and 0.088 M Mn2+? For Mn(OH)2, Ksp = 1.6 × 10-13, and for Cu(OH)2, Ksp = 4.8 × 10-20. When pH = _____ – _____ Mn(OH)2 will be soluble, but some Cu(OH)2 will precipitate out of solution.