A 0.40 gram sample of NaOH (molar mass = 40.0 g/mol) was completely neutralized with 62.5 mL of H2SO4 solution. Assume the chemical equation is: H2SO4(aq) + 2NaOH(aq) Na2SO4(aq) + 2H2O(l). What is the molarity of the H2SO4 solution?
Given Reaction
H2SO4(aq) + 2NaOH(aq) Na2SO4(aq) + 2H2O(l).
Step 1: From the given reaction, It is noted that 2 mole of NaOH require 1 mole of Sulfuric Acid
Step 2: We have to find out mole of NaOH for the given amount(Weight)
i.e., 40g of NaOH = 1M[NaOH]
Therefore, 0.4g of NaOH= 0.01 M[NaOH]
Step 3: From the given reaction
For 2M of NaOH, 1M of H2SO4 is required. Therefore 0.01 M of NaOH requires 0.005M of H2SO4
Ans: Molarity of the 62.5 mL H2SO4 solution = 0.005M
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