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A 0.40 gram sample of NaOH (molar mass = 40.0 g/mol) was completely neutralized with 62.5...

A 0.40 gram sample of NaOH (molar mass = 40.0 g/mol) was completely neutralized with 62.5 mL of H2SO4 solution. Assume the chemical equation is: H2SO4(aq) + 2NaOH(aq)  Na2SO4(aq) + 2H2O(l). What is the molarity of the H2SO4 solution?

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Answer #1

Given Reaction

H2SO4(aq) + 2NaOH(aq) Na2SO4(aq) + 2H2O(l).

Step 1: From the given reaction, It is noted that 2 mole of NaOH require 1 mole of Sulfuric Acid

Step 2: We have to find out mole of NaOH for the given amount(Weight)

i.e., 40g of NaOH = 1M[NaOH]   

Therefore, 0.4g of NaOH= 0.01 M[NaOH]   

Step 3: From the given reaction

For 2M of NaOH, 1M of H2SO4 is required. Therefore 0.01 M of NaOH requires 0.005M of H2SO4

Ans: Molarity of the 62.5 mL  H2SO4 solution =  0.005M

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