draw the lewis structure of KrF2O2
The valence electronic configuration of Kr = 4s24p6 (8 valence electrons)
The valence electronic configuration of F = 2s22p5 (7 valence electrons), which needs 1 electron to fulfil octet rule.
The valence electronic configuration of O = 2s22p4 (6 valence electrons), which needs 2 electrons to fulfil octet rule.
In the compound KrF2O2, the oxidation state of Kr = +6, i.e. 6 valence electrons of the Kr undergoes bonding, whereas the the remaining 2 valence electrons are non-bonding.
Hence the Lewis structure of KrF2O2 can be drawn as shown below.
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