a. Match the following aqueous solutions with the appropriate letter from the column on the right.
1. | 0.25 m | NaCl | A. | Highest boiling point | ||
2. | 0.20 m | K2CO3 | B. | Second highest boiling point | ||
3. | 0.28 m | BaS | C. | Third highest boiling point | ||
4. | 0.53 m | Ethylene glycol(nonelectrolyte) | D. |
Lowest boiling point |
b.
1. | 0.18 m | BaCl2 | A. | Highest boiling point | ||
2. | 0.19 m | FeI2 | B. | Second highest boiling point | ||
3. | 0.20 m | CoI2 | C. | Third highest boiling point | ||
4. | 0.50 m | Ethylene glycol(nonelectrolyte) | D. | Lowest boiling point |
a ) answer : 2 -A , 4 -B , 3- C , 1 -D
explanation:
for NaCl , i = 2 number of ions 2 they are Na+ , Cl- so i =2
1) 0.25 m NaCl means = 0.25 x 2 = 0.50 m NaCl
2) 0.20 m K2CO3 = 0.20 x 3 = 0.60 m K2CO3
3) 0.28 m BaS = 0.28 x 2 = 0.52 m BaS
4) 0.53 m glycol = 0.53 x 1 = 0.53 m glycol
now highest value will have highest boiling point.
2 ) 0.60 m K2CO3 -----------> Highest boiling point
4) 0.53 m glycol -----------> second Highest boiling point
3) 0.52 m BaS---------> third Highest boiling point
1) 0.50 m NaCl -----------> lowest Highest boiling point
b) answer : 3 - A , 2 -B , 1 -C , 4 -D
same above explanation:
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