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You need to prepare an acetate buffer of pH 6.33 from a 0.727 M acetic acid...

You need to prepare an acetate buffer of pH 6.33 from a 0.727 M acetic acid solution and a 2.16 M KOH solution. If you have 475 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 6.33? The pKa of acetic acid is 4.76.

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Answer #1

millimoles of acetic acid = 0.727 x 475 = 345. 325

millimoles of KOH = 2.16 V

CH3COOH +    KOH   --------------> CH3COO- + H2O

    345. 325         2.16 V                           0                0

345. 325 - 2.16 V     0                            2.16 V

pH = pKa + log [salt / acid]

6.33 = 4.76 + log [2.16 V /345. 325 - 2.16 V ]

[2.16 V /345. 325 - 2.16 V ] = 37.154

2.16 V = 12830 - 80.253 V

V = 155.68 mL

volume of KOH = 156 mL

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