Question

The activation barrier for an uncatalyzed reaction is estimated to be 15.3 kcal/mol. The activation barrier...

The activation barrier for an uncatalyzed reaction is estimated to be 15.3 kcal/mol. The activation barrier for the catalyzed reaction is estimated to be 8.7 kcal/mol. How many times faster is the catalyzed rate versus the uncatalyzed rate? In other words, by what factor/coefficient do you have to multiply the uncatalyzed rate to equal the catalyzed rate? Assume the temperature is 298 K, and enter your answer to the nearest ones.

Homework Answers

Answer #1

K1 = Ae-Ea1/RT uncatalysed

k2   = Ae-Ea2/RT catalysed

K1/K2    = Ae-Ea1/RT uncatalysed/Ae-Ea2/RT catalysed

K1/K2    = e-Ea1/RT/e-Ea2/RT

            = -Ea1/RT/-Ea2/RT

           = Ea1/Ea2

          = 15.3/8.7 = 1.758

K1/K2 = 1.758

K1   = 1.758K2

K2/K1   = 0.568

K2      = 0.568K1

catalyses rate 0.568 times faster than un catalysed rate

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