The activation barrier for an uncatalyzed reaction is estimated to be 15.3 kcal/mol. The activation barrier for the catalyzed reaction is estimated to be 8.7 kcal/mol. How many times faster is the catalyzed rate versus the uncatalyzed rate? In other words, by what factor/coefficient do you have to multiply the uncatalyzed rate to equal the catalyzed rate? Assume the temperature is 298 K, and enter your answer to the nearest ones.
K1 = Ae-Ea1/RT uncatalysed
k2 = Ae-Ea2/RT catalysed
K1/K2 = Ae-Ea1/RT uncatalysed/Ae-Ea2/RT catalysed
K1/K2 = e-Ea1/RT/e-Ea2/RT
= -Ea1/RT/-Ea2/RT
= Ea1/Ea2
= 15.3/8.7 = 1.758
K1/K2 = 1.758
K1 = 1.758K2
K2/K1 = 0.568
K2 = 0.568K1
catalyses rate 0.568 times faster than un catalysed rate
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