Question

A solution is prepared by dissolving 61.5 mL of methanol in
115.0 mL of water at 25 ∘C . The final volume of the solution is
173.4 mL . The densities of methanol and water at this temperature
are 0.782 g/mL and 1.00 g/mL , respectively. For this solution,
calculate each of the following. [Molarity, molality, mass
percent]

Answer #1

mass of methanol = volume * density

= 61.5*0.782 = 48.093 gm

mass of water = 115*1 = 115gm

molarity = weight of solute*1000/gram molar mass*volume of solution in ml

= 48.093*1000/32*173.4

= 48093/5548.8 = 8.66M

molality = weight of solute*1000/gram molar mass*Weight of solvent in gm

= 48.093*1000/32*115

= 48093/3680 = 13.068m

mass % =

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molality
mass %
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