Question

An air/gasoline vapor mix in an automobile cylinder has an initial temperature of 165 ∘C and a volume of 12.6 cm3 . If the mixture is heated to 574 ∘Cwith the pressure and amount held constant, what will be the final volume of the gas in cubic centimeters?

Answer 1

Given,

The temperature (T₁) = 165 ^oC + 273.15 = 438.15 K

Volume.(V₁) = 12.6 cm³ x ( 1dm³ / 1000 cm³) = 0.0126 dm³OR 0.0126 L

The temperature(T₂) = 574 ^oC + 273.15 = 847.15 K

Volume(V₂) = ?

We know, Charles's law for two different sets of conditions,

V₁/ T₁ = V₂/T₂

Rearranging the formula,

V₂ = (V₁ x T₂) /T₁

Substituting the known values,

V₂ = (0.0126 dm³ x 847.15 K) /438.15 K

V₂ = 0.0244 dm³

Converting dm³ to cm³,

= 0.0244 dm³ x (1000 cm³ / 1 dm³)

= 24.4 cm³

Thus, the final volume of the gas is 24.4 cm³.