Question

Determine the energy of 1.60 mol of photons for each of the following kinds of light....

Determine the energy of 1.60 mol of photons for each of the following kinds of light. (Assume three significant figures.)

infrared radiation (1580 nm )

visible light (515 nm )

ultraviolet radiation (165 nm )

Homework Answers

Answer #1

n = 1.6 mol

E = hc/WL

for 1.6 mol:

E= h*c/WL * (Na *1.6)

change all WL to meters

then

H = planck constant = 6.636*10^-34

c = speed of light = 3*10^8

then

a)

IR

E= h*c/WL * (Na *1.6)

E=(6.636*10^-34)(3*10^8)/(1580*10^-9)* (6.022*10^23)*(1.6) = 121403.52 J/mol --> 1.21*10^5 kJ/mol

b)

Visible Light

E= h*c/WL * (Na *1.6)

E=(6.636*10^-34)(3*10^8)/(515*10^-9)* (6.022*10^23)*(1.6) = 372461.28466J/mol --> 3.72*10^5 kJ/mol

c)

UV light

E= h*c/WL * (Na *1.6)

E=(6.636*10^-34)(3*10^8)/(165*10^-9)* (6.022*10^23)*(1.6) = 1162530.67636 J /mol --> 1.16*10^6 kJ/mol

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