I have an overall equation of:
2CrCl3 * 6H2O + Zn + 4 NaOAc * 3 H2O = [Cr(OAc)2]2 * 2 H2O + ZnCl2 + 22 H2O + 4 NaCl
The question is, "Why do we wash with water, ethanol, and ether?" The washing process is in that order and I know that ZnCl2 and NaCl is soluble in water, but I'm not quite sure why we wash with the ethanol and ether. Could someone please help?
Answer:
During the washing process the unreacted material and the side products comeout. Here first water wash is giving that means water soluble compouds like salts (ZnCl2 and NaCl) comeout.
Then giving the Ethanol wash the excess of the water comeout due to the water can be soluble in Ethanol by the formation of the H-bonds.
Lastly we are giving the ether wash this is for the dryness of the compound. After giving the ether wash will dry under the vaccume.
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