Question

Consider the following reaction: A(g)⇌2B(g) Find the equilibrium partial pressures of A and B for each of the following different values of Kp. Assume that the initial partial pressure of B in each case is 1.0 atm and that the initial partial pressure of A is 0.0 atm. Make any appropriate simplifying assumptions. Kp=1.8 Find Pa and Pb.

Answer 1

                                      

             A(g) ⇌ 2B(g)
initial     0 atm     1 atm

change       x atm     2x atm

equilibrium x atm     1-2x atm

     kp = pB^2/pA

     1.8 = (1-2x)^2/x

   x = 0.2 atm

at equilibrium,

partial pressure of A (pA)= x = 0.2 atm

partial pressure of B (pB) = 1-2x

             = 1-2*0.2 = 0.6 atm