Question

A gas sample in a Boyle’s law apparatus is compressed to a volume of 22.0 mL....

A gas sample in a Boyle’s law apparatus is compressed to a volume of 22.0 mL. If its original volume was 37.0 mL at 12,000 Pa, what is the new pressure of the gas sample? Show your calculations

Homework Answers

Answer #1

Since the apparatus is Boyle's law apparatus, it means we are studying the variation of pressure with Volume in conditions of constant temperature and number of moles. n and T is Ideal gas equation below are constant which makes the right hand side to be constant.

PV = nRT = constant

P1V1 = P2V2

P1 = 12,000 Pa, V1 = 37 mL, V2 = 22 mL , P2 needs to be calculated.

P2 = P1V1/V2 = 12000 Pa x 37 mL / 22 mL = 20181.82 Pa

New pressure of the gas sample is 20181.82 Pascal

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