A gas sample in a Boyle’s law apparatus is compressed to a volume of 22.0 mL. If its original volume was 37.0 mL at 12,000 Pa, what is the new pressure of the gas sample? Show your calculations
Since the apparatus is Boyle's law apparatus, it means we are studying the variation of pressure with Volume in conditions of constant temperature and number of moles. n and T is Ideal gas equation below are constant which makes the right hand side to be constant.
PV = nRT = constant
P1V1 = P2V2
P1 = 12,000 Pa, V1 = 37 mL, V2 = 22 mL , P2 needs to be calculated.
P2 = P1V1/V2 = 12000 Pa x 37 mL / 22 mL = 20181.82 Pa
New pressure of the gas sample is 20181.82 Pascal
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