Question

Determine the pH of water solutions with the following characteristics. Classify each solution as acidic, basic, or neutral.

(a) [OH negative]=9.4 *10 to the negative 4 power

(b) [OH negative]=10.[H positive]

(c) [H positive]=2.3 * 10 to the negative 2 power

(d) [OH negative]=5.1 * 10 to the negative 10 power

Please show work in obvious steps and clear handwriting. Thank you so much!

Answer 1

Use the calculator pH=-log[H⁺]

a)- [H⁺]=1.0*10^-14/9.4*10^-4

             =0.106382978*10^-10M

PH=-log(0.106382978*10^-10M) =0.97(acidic)

b)[OH]=4.[ 0.106382978*10^-10M]=4.25*10^-11           

[H+]=1.0*10^-14/4.25*10^-11

=0.235294117*10^-3

⁼3.62(less acidic)

c) PH=-log(2.3*10^-2)=1.63(acidic)

d) [H⁺]=1.0*10^-14/5.1*10^-10

             =0.196078431 *10^-4M

Ph=4.71(nearly neutral)