Question

which of the following processes would cause the volume of the gas sample to double?

a) the pressure applied to the gas is increased from 1.00 atm to 2.00 atm

b) the temperature of the sample is increased to 298k to 596 k

c) the pressure applied to the gas is decreased from 4.00 atm to 1.00 atm

d) the number of moles of gas in the container is halved

Answer 1

a) we know that

PV = nRT

at constant temperature

P1V1 = P2V2

P1/P2 = V2/V1

given

V2 = 2 V1

V2/V1 = 2

so

P1/P2 = 2

so

P2 = P1/2

so

pressure should be halved

so options a and c are not correct

at constant pressure

V2/V1 = T2/T1

2 = T2/T1

T2 = 2 T1

so

the temperature should be doubled

so option b is correct

now

V2/V1 = n2/n1

2 = n2 / n1

n2 = 2 n1

so

number of moles should be doubled

so option d is false

So the answer is b) the temperature increased from 298 to 596 K