Question

. Calculate the Qsp for the mixing of 30.0 mL of 3.7 × 10-3 M Sr(NO3)2...

. Calculate the Qsp for the mixing of 30.0 mL of 3.7 × 10-3 M Sr(NO3)2 and 25.0 mL of 0.02 M Na2SO4, and state whether a precipitate will form?

A. Qsp = 2.8 × 10^-7; No.

B. Qsp = 2.8 × 10^-7; Yes.

C. Qsp = 1.8 × 10^-5; No.

D. Qsp = 1.8 × 10^-5; Yes.

The answer is B. How does one get the answer?

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Homework Answers

Answer #1

moles of Sr(NO3)2 in 3.7*10-3M and 30ml = Molarity* Volume (L)(3.7*10-3)*30/1000 =0.000111

Moles of Na2SO4 = 0.02*25/1000=0.0005 moles

Volume after mixing = 30+25= 55ml

Concentrations : Sr(NO3)2 : 0.000111*1000/55=0.002018 and Na2SO4= 0.0005*1000/55=0.009091M

The following reaction takes place leading to formation of SrSO4

Sr(NO3)2(aq) + Na2SO4(aq) ------> SrSO4(s) + 2 NaNO3(aq)

Sr+2 +SO4-2 --------> SrSO4(s)

QSP= 0.002018*0.009091 =1.8*10-5

Precipitate forms

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