Question

Consider the reaction

2A+3B-> C +4D

You mix 500ml of 1.0M A, and 500ml of 1.4 M B. At equilibrium, you detect C to have a concentration of 0.218M. What is the equilibrium constant for this reaction?

Answer 1

Given reaction 2A+3B-> C +4D

but the term "D" is not involved in the determination of equilibrium constant as its concentration is not mentioned,

A concentration will be = 500 mL x 10-3 L x 1.0 m = 0.5M

B concentration will be = 500 mL x 10-3 L x 1.4 m = 0.7M

when we mixed these two total volume becomes 1000 mL = 1L, hence C concentration remains unchanged

as molarity (M) = moles / liter

K_eq = [C] / [2A]² [3B]³ = 0.218 / [2 x 0.5]² [ 3 x 0.7]³ = 0.02354

K_eq = 0.02354

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