Question

Calculate the number of moles in 6ml of isopentyl alcohol, and the number of moles in 8 ml of acetic acid. Which reagent is limiting?

Answer 1

first convert the mL in grams using density

density = mass / volume

Mass = density x volume

6ml of isopentyl alcohol

mass = 6 mL x 0.8104 g/mL (density of isopentyl alcohol = 0.8104 g /ml

mass = 4.86 grams

moles = weight in grams / molar mass in grams

moles = 4.86 g / 88.148 g/mol

moles = 0.05513 mol

8 ml of acetic acid

mass = 8 mL x 1.049 g/mL

= 8.392 gram

moles = 3.392 gram / 60.05 g/mol

moles = 0.05648 moles

so limiting agent  isopentyl alcohol