Question

Consider the titration of a 27.0 −mL sample of 0.175 MCH3NH2 with 0.150 M HBr. Express answers using two decimal places. Determine each of the following.

A) the initial pH

B) the volume of added acid required to reach the equivalence point

C) the pH at 6.0 mL of added acid

D) the pH at one-half of the equivalence point

E) the pH at the equivalence point

F) the pH after adding 4.0 mL of acid beyond the equivalence point

Answer #1

**A) pOH = 1/2[pKb-logC]= 1/2[3.36-log(0.00472)]=
2.84**

**pH = 14-2.84 = 11.16**

**B) M1V1 = M2V2**

**0.175*27 = 0.15*V2**

**V2 = 31.5 mL**

**C) After adding 6.0 mL of acid**

**[base] = 27*0.175/33 =0.143 ; [acid]= 6*0.15/33 =
0.027**

**base left = 0.143-0.027 = 0.116**

**pOH = pKb+log(salt/base) = 3.36+log(0.027/0.116) =
2.73**

**pH = 14-2.73 = 11.27**

**D) [base]= 27*.175/42.75 = 0.11 ; [acid]=15.75*.15/42.75
= 0.055**

**base left = 0.11-0.055 = 0.055**

**pOH = 3.36+log(0.055/0.055) = 3.36**

**pH = 14-3.36 = 10.64**

**E) equivalence point, [salt] = 31.5*0.15/58.5
=0.081**

**pH = 7-1/2(pKb+logC) = 7-1/2(3.36+log(0.081)) =
5.86**

**F) 31.5+4 = 35.5 ml of acid**

**[base] = 27*.175/62.5 =0.0756; [acid] = 35.5*.15/62.5 =
0.0852**

**acid left = 0.0852-0.0756 =0.0096**

**pH = -log(0.0096) = 2.02**

Consider the titration of a 26.0 −mL sample of 0.175 M CH3NH2
with 0.150 M HBr. Determine each of the following.
1. the pH at 4.0 mL of added
acid
2.the pH at the equivalence point
3.the pH after adding 6.0 mL of acid beyond the equivalence
point

Consider the titration of a 27.0-mLmL sample of 0.175 MM
CH3NH2CH3NH2 with 0.150 MM HBrHBr. (The value of KbKb for
CH3NH2CH3NH2 is 4.4×10−44.4×10−4.)
Determine the volume of added acid required to reach the
equivalence point.
Determine the pHpH after adding 4.0 mLmL of acid beyond the
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Consider the titration of a 27.0 −mL sample of 0.180 M CH3NH2
with 0.145 M HBr. Determine the pH after adding 6.0 mL of acid
beyond the equivalence point.

Consider the titration of a 25.0 −mL sample of 0.180 M CH3NH2
with 0.155 M HBr. Determine each of the following.
a. the pH at one-half of the equivalence point
b. the pH at the equivalence point
c. the pH after adding 6.0 mL of acid beyond the equivalence
point
i already found that the initial pH is 11.95, the volume of acid
added to reach equivelance point is 29.0mL, and the pH og 6.0mL of
added acid is 11.23

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Part B
Determine the volume of added acid required to reach the
equivalence point. answer to 3 sig figs
Part C
Determine the pH at 6.0 mL of added acid
Part D
Determine the pH at one-half of the equivalence point.
Part E
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Volume of added acid required to reach the equivalence point:
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eight
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express answer using three decimal places
PartD the pH at the equilalence point
express answer as a whole number
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