Question

# How much heat would it take to convert 60.0 g ice at 0.00˚C into liquid water...

How much heat would it take to convert 60.0 g ice at 0.00˚C into liquid water at 20.0˚C?

The trend in polarizability from left to right across a period in the Periodic Table is due to …

 a. decreasing electronegativity. b. decreasing ionization energy. c. increasing mass. d. decreasing atomic size.

1.

Step 1

Heat required to melt ice

H1= Mass × Heat of fusion of ice

= 60.0 g × 334 J/g

= 20040 J.

Step 2

Heat required to increase the temperature of liquid water from 00 c to 200 c

H2 = Mass × specific heat × temperature

= 60 g × 4.184 J/goc × (20 - 0)o c

= 5020.8 J.

Total heat needed

= H1 + H2

= (20040 + 5020.8 ) J

= 25060.8 J.

2.

Polarizability decreases from left to right across a period.

Larger atoms are more polarizable. Smaller atoms are less polarizable.

So , periodic trend in polarizability is due to decreasing atomic size.

Option d is correct.

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