Question

a) describe the procedure, showing all calculations, for making 600ml of.02M lead acetate solution.

b) show all calculations for diluting the solution in question a to. 0.05M and in a volume of 250ml. indicate how many ml. of stock solution is needed

Answer 1

Procedure

1 Now x gm of lead acetate is weighted and tranferred inta a watch glass.

2. Now a measuring flask.was taken

3. Now transferred the x gm of lead acetate into the measuring flask by washing and filled by distilled water upto 600 mL Labeled mark

CALCUATION

Now Calculation for x gm of lead acetate

We know the molar mass of lead acetate is 325 gm/mol

Here Volume is 600 mL

Molarity 0.02M

We know

Hence 3.91 gm of lead acetate is required

b. Now we know that

For 240mL , 3.91 gm is required

For 250 mL , the amount is

Hence 4.07 gm is required to get 0.05M of Lead acetate in a volume of 250mL