Question

Part A Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 4.3×10−4 M .

Part B Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 1.6×10−12 M .

Part C Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 3.0×10−2 M .

Answer 1

Kw = [H+] [OH-] = 1.0 x 10-14 at 25°C

Part A Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 4.3×10−4 M .

Here ; [OH−]= 4.3×10−4 M .

[H+] = 1.0 x 10-14 /[OH-]

[H+] = 1.0 x 10-14 /4.3×10−4

[H+] =2.3 x 10-11M

Part B Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 1.6×10−12 M .

Here ; [OH−]= 1.6×10−12 M .

[H+] = 1.0 x 10-14 /[OH-]

[H+] = 1.0 x 10-14 /1.6×10−12

[H+] =6.3 x 10-3M   

Part C Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 3.0×10−2 M .

Here ; [OH−]= 3.0×10−2 M .

[H+] = 1.0 x 10-14 /[OH-]

[H+] = 1.0 x 10-14 /3.0×10−2

[H+] =3.3 x 10-13M