Question

Calculate the mass of sodium acetate trihydrate (CH3COONa●3H2O) solid and the volume of 1.00 M acetic...

Calculate the mass of sodium acetate trihydrate (CH3COONa●3H2O) solid and the volume of 1.00 M acetic acid (CH3COOH) required to make 250.0 mL of 0.500 M buffer, pH 5.00.

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Homework Answers

Answer #1

pH = pKa + log [salt]/[Acid]

Let us assume [salt] = x and [acid] = y

5 = 4.75 + log(x/y)

x/y = 1.7783

x + y = 0.5 * 250/1000 = 0.125

by solving the above equation,

x = 1.7783*(0.125-x)

x = 0.08 mol/L = cocncentration of sodium acetate

y = 0.125 - 0.08

y = 0.045 mol/L = concentration of acetic acid

we have M1V1 = M2V2

0.045 * 250 = 1 * V2

V2 = volume of acetic acid = 11.25 mL required.

mass of sodium acetate = ?

from the formula of molarity

0.08 = m/136 * 1000/250

m = mass of sodium acetate = 2.72 g

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