Question

Part A

A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If the final temperature of the system is 21.30  ∘C , what is the mass of the steel bar?

Use the following values:

specific heat of water = 4.18 J/(g⋅∘C)

specific heat of steel = 0.452 J/(g⋅∘C)

Express your answer to three significant figures and include the appropriate units.

The specific heat of water is 4.18 J/(g⋅∘C). Calculate the molar heat capacity of water.

Express your answer to three significant figures and include the appropriate units.

Answer 1

Temperature change for water
Assuming density of water to be 1 g/ml, the mass (m) of 80 ml of water
Specific of water,
Heat lost by water
It is also equal to heat gained by steel bar.
Temperature change for steel bar
Specific of steel bar, S' =0.452 J/g . ^oC
Mass of steel bar = m'
Heat gained by steel bar


Hence, the mass of the steel bar is 26.8 g.

The specific heat of water is 4.18 J/(g⋅∘C). The molar mass of water is 18 g/mol. The molar heat capacity of water is J/(g⋅∘C) .