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Calculate the final pH of 25 ml of buffer 0.1 M CH3COOH / CH3COONa, pH=3.50, after...

Calculate the final pH of 25 ml of buffer 0.1 M CH3COOH / CH3COONa, pH=3.50, after the addition of 1.00 ml of 0.1 M HCl

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Answer #1

[CH3COOH] + [CH3COO-]= 0.1M

pH= pKa + log[A-]/[HA]

pKa= 4.76

3.5 - 4.76 = log[CH3COO-]/[CH3COOH]

0.055= [CH3COO-]/[CH3COOH]

[CH3COO-]= 0.055 x [CH3COOH]

Now put [CH3COO-] in the first equation:

0.055 x [CH3COOH] + [CH3COOH]= 0.1

[CH3COOH]= 0.095M

[CH3COO-]= 5.21x10-3M

mol of HCl= 1x10-3L x 0.1M= 1x10-4 mol

[HCl]= 1x10-4 mol/26x10-3L= 0.004M

The HCl will react with the CH3COO. to produce CH3COOH

final [CH3COOH]= 0.095 + 0.004= 0.099M

final [CH3COO-]= 5.21x10-3 - 0.004= 1.21x10-3M

pH= 4.76 + log 1.21x10-3M/0.099M = 2.85

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