Question

Calculate the pH when 27.3 mL of 0.0013 M HCl is added to 100.0 mL of pure water. Comment and hint in the general feedback.

Answer 1

We have 27.3 mL=0.0273 L of 0.0013M HCl

We know

The number of moles are

after addition of 27.3 mL of 0.0013M of HCl to 100 mL of pure water , the total volume is 127.3 mL

That means volume (v)= 127.3 mL=0.1273 L

we have in 0.1273 L

that means 0.1273 L contain

then 1 L contain

As HCl ionized completely in water , that the concentration of

We know

Hence the pH is 3.56 and it is acidic solution.