Question

Data & Analysis

Reaction Setup:

Chemical	Mass or Volume**	mmol
Acetic acid	60.05
Potassium cyanate	.57g
p-Phenetidine	.71g
Water*		(n/a)

* Give the total volume used for performing the reaction itself (not including purification processes).

** Make sure you use your actual recorded data from during lab (right column in your lab notebook) with correct units, not your planned procedures (left column). If you did not record the actual measurement, you do not actually have usable data.

Calculations for measured amounts to mmol:

Answer 1

molecular weight of acetic acid = 60.05 g = 1mole

mole can be converted to mmol by dividing it by 1000

then for 1mmol = 60.05/1000 = 0.06005 = 60.05 mg

therefore for 60.05 mg = 1 mmol

molecular weight of potassium cyanate = 81.11 g = 1 mole

then for 1mmol = 81.11 mg

0.57 x1000 = 570 mg

mmol for 570 mg = 570 /81.11 = 7.027 mmol

molecular weight of p-Phenetidine = 137.182 g

then for 1mmol = 137.182 mg

then mmol for 0.71 g

0.71 g x 1000 = 710 mg

mmol for 0.71 g = 710/137.182 = 5.17 mmol