Question

A gas stream which is 70.0 mol% CO₂ and 30.0 mol% N₂ is flowing at a rate of 225 kilograms per minute. What is the volumetric flow rate of this gas mixture, in units of cubic meters per minute, if the gauge pressure is 1.50 bar and the temperature is 300.0 Kelvin?

* I know the answer is 95.4 cubic meters per minute, I need to know the steps of how to solve the problem. Thanks!

Answer 1

consider per 1 minute

total mass = 225 kg

let

total moles of gas = y

then

moles of CO2 = 0.7y

moles of N2 = 0.3y

now

we know that

mass = moles x molar mass

so

mass of CO2 = 0.7y x 44 = 30.8y

mass of N2 = 0.3y x 28 = 8.4y

now

total mass = 225 kg = 225 x 1000 g

so

30.8y + 8.4y = 225 x 1000

y = 5739.80

total moles of gas = y = 5739.80

now

we know that

PV = nRT

so

1.5 x V = 5739.8 x 0.0821 x 300

V = 94247 L

now

we know that

1 L = 10-3 m3

so

V = 94247 x 10-3 m3

V = 94.247 m3

so

the volumetric flow rate is 94.247 m3