In the correct equation for the reaction of sodium with water, the sum of the simplest whole-number coefficients is:
The balanced equation is : 2Na(s) + 2H2O (l) 2NaOH(aq) + H2(g)
Here the coefficient of Na is 2
the coefficient of H2O is 2
the coefficient of NaOH is 2
the coefficient of H2 is 1
Therefore the sum of the coefficients of reactants is 2+2 = 4
the sum of the coefficients of products is 2+1 = 3
The sum of the coefficients of both reactants & products is 4+3=7
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