Question

The lead-containing reactant(s) consumed during recharging of a lead storage battery is/are

Pb(s) only

PbO₂(s) only

PbSO₄(s) only

both PbO₂(s) and PbSO₄(s)

both Pb(s) and PbO₂(s)

THE ANSWER IS PbSO4(s) only ....BUT WHY, PLEASE GO INTO DETAIL.

Corrosion of iron is retarded by

the presence of salts

high pH conditions

low pH conditions

both the presence of salts and high pH conditions

both the presence of salts and low pH conditions

THE ANSWER IS high pH conditions PLEASE GO INTO DETAIL

What current (in A) is required to plate out 1.22 g of nickel from a solution of Ni²⁺ in 1.0 hour?

	65.4
	4.01 x 103
	1.11
	12.9
	2.34 THE ANSWER IS 1.11 PLEASE GO INTO DETAIL

Answer 1

PbSO4 (s) + H⁺ + 2e^- ------> Pb(s) + HSo4^- at cathode

PbSo4 + 2H2O --------> Pb(s) + PbO2(s) + 3H⁺ (aq) + HSO4^- (aq) + 2e^-    at anode

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2PbSo4 + 2H2O --------> Pb(s) + PbO2(s) + 2H⁺ (aq) + 2HSO4^- (aq) rechare the battery

PbSO₄(s) only >>>> answer

corrosion of iron at high pH conditions.

The electrochemical corrosion is considered as the anodic dissolution as the anodic of the metal undergoes corrosion.

W = MCt/ZF

   Ni⁺² + 2e^- -------> Ni

           Z = 2

            F= 96500c

   t = 60*60 = 3600sec

1.22 = 58.67*C*3600/2*96500

C = 1.22*2*96500/58.67*3600   = 1.11A