Question

What is the volume of a mercury sample that has a total number of 2.45*10^25 protons?

Given: density of Hg=13.53g/mL and Periodic Table

Answer 1

one atom of mercury contains = 80 protons
6.023 x 10²³ atoms of mercury contains = 80 x 6.023 x 10²³ protons

or
80 x 6.023 x 10²³ protons = 1 mole of Mercury
we have 2.45x10²⁵ protons ==?

no. moles of mercury = (2.45x10²⁵ x 1) /(80 x 6.023 x 10²³ )
           = 0.508 moles

One mole of mercury molar mass = 200.59 amu
the mass of 0.508 moles of mercury = 200.59 x 0.508 = 102 g

Given, density of mercury = 13.53 g/mL

density = mass/volume
13.53 g/mL = 102 g/volume
The volume of the mercury sample = 102 g / 13.53 g/mL =   7.54 mL