Question

A) Calculate Kc for the reaction below.
I2(g)⇌2I(g)Kp=6.26×10−22 (at 298 K)

B) Calculate Kc for the reaction below.

CH4(g)+H2O(g)⇌CO(g)+3H2(g)Kp=7.7×1024 (at 298 K)

C) Calculate Kc for the reaction below.
I2(g)+Cl2(g)⇌2ICl(g)Kp=81.9 (at 298 K)

Answer 1

A) Calculate Kc for the reaction below.
I2(g)⇌2I(g)

Kp=6.26×10−22 (at 298 K)

We know that

Kp = Kc(RT)^Δn

Where Δn = Moles of gaseous products- moles of gaseous reactants = 2-1 = 1

Kc = Kp (RT)^-Δn

Kc = 6.26×10⁻²² (0.0821 X 298)^-1 = 2.56 X 10^-23

B) Calculate Kc for the reaction below.

CH4(g)+H2O(g)⇌CO(g) + 3H2(g)

Kp=7.7×10²⁴ (at 298 K)

We know that

Kp = Kc(RT)^Δn

Where Δn = Moles of gaseous products- moles of gaseous reactants = 4-2= 2

Kc = Kp (RT)^-Δn

Kc = 7.7×10²⁴ (0.0821 X 298)^-2 = 1.29 X 10²⁰

C) Calculate Kc for the reaction below.
I2(g)+Cl2(g) ⇌ 2ICl(g)

Kp=81.9 (at 298 K)

We know that

Kp = Kc(RT)^Δn

Where Δn = Moles of gaseous products- moles of gaseous reactants = 2-2 = 0

Kc = Kp (RT)^-Δn = Kp = 81.9