Question

A pump increases the pressure of in liquid water from 100 kPa at 25°C to 2,500 kPa. What is the minnimum horsepower motor required to drive the pump for a flow rate of 0.005 m³/s

Answer 1

i can only give the basic formula for determining the horsepower of this pump

and that is

horsepower = (flow rate) x (required pressure)/1714

that comes out to be

flow rate is given in m3/sec we have to convert it to g/min

1 m3 = 1000l , for water = 1000 Kg ,

hence floerate =5kg/sec, or 5000x 60 per min

3x 10⁶ g/min

and to convert kpa to psi

1 kpa = 0.145 psi

so change in pressure = (2500-100) x 0.145

348 psi

hence substituting values

HP= 300000 x 348/1714

6.1 x 10⁴ HP