Caclulate the pH of:
a 0.200 M solution of NaCH3COO
a 0.200 M solution of NH4NO3
a 0.200 M solution of NaCl
CH3COOH 1.76 * 10-3
NH4+ 5.68 * 10-10
HCl >1
Predict whether the following would be acidic, basic, or neutral in solution:
0.5 M NaCN
0.5 M KCl
0.5 M Ba(NO3)2
0.5 M NH4C2H3O2
I)
a) 0.200 M solution of NaCH3COO
since the salt is made up of weak acid and strong base the resultant solution will be basic in nature
C=0.200M
Ka of CH3COOH 1.76 * 10-3
pH=7 +1/2(pKa + logC)
pH=7+1/2(-log(1.76*10^-3)+log(0.2))=8.03
b)0.200 M solution of NH4NO3
since the salt is made up of strong acid and weak base the resulting solution will be acidic
pH=7-1/2(pKb+logC)
pH=7-1/2((-log(5.68 * 10-10)+log(0.2))=2.7
c) since the salt is made up of strong acid and strong base so the resulting solution will be neutral
therefore the pH valueis 7
II)
0.5 M NaCN :basic
0.5 M KCl : neutral
0.5 M Ba(NO3)2 :neutral
0.5 M NH4C2H3O2 neutral(it is a salt of weak acid and weak base)
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