What is the pH after 0.050 mol NaOH is added to 1.00 L of a buffer that is 0.550 M (CH3)3N and 0.550 M (CH3)3NHCl? Kb= 7.4 x 10^-5
pH after 0.050 mol NaOH = 9.95
Coins can be redeemed for fabulous gifts.
Log In
Sign Up
Get Answers For Free Most questions answered within 1 hours.