Which salt would raise the boiling point of a solvent the most?
a. 1.4 m Na2SO4
b. 4.0 m CH3OH
c. 1.4 m NaCl
d. 1.0 m CaCl2
The answer should be a but could someone explain why?
ΔTb = i*Kb*m
ΔTb is the elevation in boiling point
ΔTb will be maximum when i*m is maximum
Boiling temperature is maximum when ΔTb will be maximum
i is the number of ions that a compound can break into
1)
Na2SO4 will dissociate into 2 Na+ and 1 SO42-
i = 3
so,
i*m = 3*1.4 = 4.2
2)
CH3OH
It doesn’t dissociate
i = 1
i*m = 1*4.0 = 4.0
3)
NaCl
i=2
i*m = 2*1.4 = 2.8
4)
i=3 because it is non electrolyte
i*m = 3*1.0 = 3.0
i*m is maximum for a
So, a is the answer
Answer: a
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