Question

given [A3O]initial =.400 M and [X2]initial - 1.000 M calculate the equilibrium concentration of A3O according...

given [A3O]initial =.400 M and [X2]initial - 1.000 M calculate the equilibrium concentration of A3O according to the following balanced equation

2A3O+X2=3A2+2XO

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Answer #1

2A3O + X2 <-------> 3A2 + 2XO

Kc = [ A2 ]^3 [ XO ]^2/[ A3O ]^2 [ X2 ]

Initial concentration

[A3O] = 0.400M

[ X2 ] = 1.000M

[ A2 ] = 0

[ XO ] = 0

Change in concentration

[ A3O ] = -2x

[ X2] = - x

[ A2 ] = +3x

[ XO ] = +2x

Equillibrium concentration

[ A3O ] = 0.400 - 2x

[ X2 ] = 1.000 - x

[ A2 ] = 3x

[ XO ] = 2x

Therefore,

Kc = (3x)^3 ( 2x )^2/(0.400 - 2x)^2 ( 1.000 - x )

If you know Kc value , you can solve for x

substitutig the value x in [ A3O ] = 0.400 - 2x , you will get the equillibrium concentration of A3O

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