Question

the rate constant for the reaction shown below is 2.6x10^-8 L/mol*s when the reaction proceeds at 300K. The Activation Energy is 98000J/mol. Determine the magnitude of the frequency factor for the reaction. If the temperature changed to 310K, there rate constant would change. The ration of K at 310 K is closest to what whole number?

Answer 1

As we know rhat

k= A e^-Ea/RT where k= rate constant , A =  frequency factor , Ea =Activation Energy , R = gas constant , T =temperature at which reaction proceed

2.6x10^-8 L/mol * s = A e^{-98000/ 8.314 * 300}   

A = 2.6x10^{-8 _/} e^{98000/ 2494.2}

= 2.6x10^{-8 _/} e^-39.29 = 2.6 * 10^-8 / 8.64 10^-18

= 0.3009 * 10¹⁰ L/mol * s

2) k2 = A e^-Ea/RT

= 0.3009 * 10¹⁰ *   e^{-98000/ 8.314 * 310}

= 0.3009 * 10¹⁰ * e^{-98000/ 2577.34}

= 0.3009 * 10¹⁰ * e^-38.023

= 0.3009 *  10^10* 3.067 * 10^-17

= 0.922 * 10^-7 L/mol s

tempearture coefficient = k_t+10 /k_t = 0.922 * 10^-7 / 2.6 * 10^-8 = .0.35 = 3.5 = ()

The ration of K at 310 K is closest to 3 whole number .