Question

Consider a mixture of equal masses of chlorine and argon gases. Which gas exerts a greater partial pressure? By what factor?

Type the name of the gas that exerts a greater partial pressure:    

By what factor?

Answer 1

given

chlorine and argon gases

equal masses

lets assume a mass of 100 g each

so

molar mass of chlorine = 35.453 g/mol

moles of chlorine = mass of chlorine/molar mass of chlorine

= 100 g / 35.453 g/mol

= 2.8206 moles

molar mass of argon = 39.948 g/mol

moles of argon = mass of argon /molar mass of argon

= 100 g / 39.948 g/mol

= 2.5032 moles

so

as no of moles of chlorine is more it exerts a greater partial pressure

now

moles of chlorine/moles of argon = 2.8206 moles/2.5032 moles = 1.1268

chlorine exerts a greater partial pressure by a factor of 1.1268