Laparoscopic surgery involves inflating the abdomen with carbon dioxide gas to separate the internal organs and the abdominal wall.
If the CO2 injected into the abdomen produces a pressure of 17 mmHg and a volume of 4.20 L at 30. ∘C, how many grams of CO2 were used?
According to Ideal gas equation
PV = nRT
n = PV/RT
P = 17 mmHg = 0.0224 atm
V = 4.20 L
T = 30 + 273 = 303 K
R = 0.0821 L.atm/mol.K
n = 0.0224*4.20/(0.0821*303)
= 0.00378 moles
mass of CO2 = moles*molarmass
= 0.00378*44
= 0.1663 g of CO2.
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