Question

# Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium chloride (NaCl), water (H2O), and carbon...

Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2). This equation is balanced as written: 2HCl(aq)+Na2CO3(aq)→2NaCl(aq)+H2O(l)+CO2(g)

A 327-mL sample of unknown HCl solution reacts completely with Na2CO3 to form 18.1 g CO2. What was the concentration of the HCl solution?

Given balanced equation is:

2HCl(aq)+Na2CO3(aq)→2NaCl(aq)+H2O(l)+CO2(g)

From the balanced chemical equation we get the information that :

2 moles of HCl reacts with -----------1 mole of Na2CO3 and forms ---44g of CO2

Means 2moles of HCl is giving------------ 44g of CO2

? moles of HCl -----------------------------------gives 18.1g of CO2

= (18.1 * 2)/44

= 0.823 moles of HCl

Concentration of 0.823moles of HCl in 327 ml of sample (molarity) = 0.823/0.327

(Since molarity= no.of moles /volume in litres)                                            = 2.52M

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