Question

Given the following concentrations typically found in a resting
muscle cell, what is the free energy change from hydrolysis of ATP
to ADP at 25 °C?

ATP = 4 mM

ADP = 9 uM

P_{i} = 4 mM

Answer #1

Here, for the ATP hydrolysis reaction,

ATP ADP +
Pi G^{o}
= -30.5 kJ/mol

We have the reaction quotient,

Q = ( [ADP] x [Pi] )/[ATP]

= [( 9 x10^{-6}) x (4 x 10^{-3} )] /(4
x10^{-3}) = 9 x 10^{-6} M

Now, using the free enrgy relation,

G = G^{o}
+ RT ln Q

We have,

G = -30500 +
8.314 x 298 x ln(9 x 10^{-6})

= -59285.14 J/mol

= -59.285 kJ/mol

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