Question

Given the following concentrations typically found in a resting muscle cell, what is the free energy...

Given the following concentrations typically found in a resting muscle cell, what is the free energy change from hydrolysis of ATP to ADP at 25 °C?
     ATP = 4 mM
     ADP = 9 uM
     Pi = 4 mM

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Answer #1

Here, for the ATP hydrolysis reaction,

ATP ADP + Pi     Go = -30.5 kJ/mol

We have the reaction quotient,

Q = ( [ADP] x [Pi] )/[ATP]

= [( 9 x10-6) x (4 x 10-3 )] /(4 x10-3) = 9 x 10-6 M

Now, using the free enrgy relation,

G = Go + RT ln Q

We have,

G = -30500 + 8.314 x 298 x ln(9 x 10-6)

= -59285.14 J/mol

= -59.285 kJ/mol

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