At 8:00 A.M., a patient receives a 1.1-μg dose of I-131 to treat thyroid cancer.
Part A
If the nuclide has a half-life of 8.0 days, what mass of the nuclide remains in the patient at 4:00 P.M. the next day? (Assume no excretion of the nuclide from the body.)
Express your answer using two significant figures.
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m = | μg |
Given:
Half life = 8.0 days = 8.0*24 hours = 1.92*10^2 hours
use relation between rate constant and half life of 1st order reaction
k = (ln 2) / k
= 0.693/(half life)
= 0.693/(1.92*10^2)
= 3.609*10^-3 hours-1
we have:
[A]o = 1.1 ug
t = 32 hours
k = 3.609*10^-3 hours-1
use integrated rate law for 1st order reaction
ln[A] = ln[A]o - k*t
ln[A] = ln(1.1) - 3.609*10^-3*32
ln[A] = 9.531*10^-2 - 3.609*10^-3*32
ln[A] = -2.019*10^-2
[A] = e^(-2.019*10^-2)
[A] = 0.980 ug
Answer: 0.980 ug
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